Ap bio lab 6: transformation...10points to the best answerer? - ap bio lab 6 answers
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Hello, I need help in this laboratory bio-6 in the AP processing:
Compare 1) on the growth of bacteria in the following sets of plates: a) control of LB LB / Xgal control amp ... .... b) recombinant LB LB / amp / Xgal recombinant c) No recombinant LB LB / amp / Xgal nonrecombinant ... D) LB / amp / Xgal recombinant LB / AMP / nonrecombinant Xgal.
2) the plate is the negative control. Explaining. control of the plate is Postive. Explaining.
3) What is the difference between the colonies and the colonies of blue-white?
4) Explain the role of ampicillin and Xgal
Thank you for ur time and help
I really appreciate it
It is one of the laboratories reported the most difficult and need help.
***** 10 points mMost answers to detailed information *****
Thank you again
Wednesday, February 17, 2010
Ap Bio Lab 6 Answers Ap Bio Lab 6: Transformation...10points To The Best Answerer?
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1. a. LB / amp / Xgal control should no colonies.
LB and the control should have no colonies, but can the growth in terms of maintenance of sterile technique have. (The oppressed amplifier in the LB / Xgal plate AMP growth of a parasitic bacteria in the first case, even if you do not) 100% supply.
b. Recombinant LB should have numerous white colonies because the cells, recombinant or not, modified or not, can grow in LB. Since there are not any Xgal, the recombinant cells are still empty.
LB / amp / Xgal recombinant colonies should be less, as is ampicillin, the growth of cells that are not processed to prevent weapons. This body should be a mixture of colonial blue and black.
c. LB recombinant was a lot of PentecostColonies and, as before.
LB / amp / Xgal nonrecombinant colonies were blue (nonrecombinant) only, but unless the control colonies, because LB amp suppress the growth of transformed cells.
d. LB / amp / Xgal recombinant colonies must have both white and blue (I hope more white than blue!). LB / amp / Xgal some nonrecombinant white colonies must (transformed) but not recombinant.
2. You do not know how to react to it. LB control is the negative control of sterile technique. A plate with Xgal and non-recombinant cells would control recombinant negative. A plate with ampicillin and non-transformed cells are negative control of the processing. So I guess the answer you seek is the negative control = LB / Xgal / AMP +transformed cells.
Negative control: control of LB (not) to growth. Positive control: LB / AMP / Xgal recombinant (only cells that can be transformed are grown in ampicillin, and only cells that are mined for the production of recombinant blue Xgal).
3. The plasmids are blue / white screening have a gene for beta-galactosidase. When inserted into plasmid DNA, beta-galactosidase, was suspended as a result. Then the plasmid of origin (can) not used to produce beta-galactosidase, which produces X-gal and blue metabolised to. Blue = Non-recombinant, recombinant = white (but not 100% guaranteed to be accurate host tried to have enter).
http://en.wikipedia.org/wiki/Blue_white_ ...
4. X-gal is the sSurface preparation beta-galactosidase. When metabolized, produces blue colonies.
Since no conversion of 100%, always contain some cells that no plasmid. Ampicillin (or another antibiotic) is used to prevent the growth of these cells. Have included only the cells, the plasmid encoding antibiotic resistance will grow in the situation.
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